Jan 27, 2012 · %s is for string %d is for decimal (or int) %c is for character. It appears to be chewing through an array of characters, and printing out whatever string exists starting at each …

Jan 10, 2018 · %d is a signed integer, while %u is an unsigned integer. Pointers (when treated as numbers) are usually non-negative. Pointers (when treated as numbers) are usually non …

Jan 10, 2010 · No, %d is a format string, signifying decimal value. 'n' will be appended. Unless it's '\n', which it probably is supposed to be, which is a newline (which will also be appended of …

Mar 30, 2012 · printf ("%*d %*d\n", 4, a, 4, b); And the reason you're getting the weird output is due to that undefined behaviour. This excellent answer shows you the sort of things that can …

Sep 28, 2012 · printf("%d\b",x) prints the characters '1', '0' (because x==10) and \b.The \b is a backspace character; if you print to a terminal, it will print 10 and then move the cursor back …

May 6, 2015 · It is better to use. scanf("%*[^\n]"); scanf("%*c"); to clear the stdin.This is because, in the former case (single scanf), %*[^\n] will fail when the first character to be scanned is the …

Possible Duplicate: Could anyone explain these undefined behaviors (i = i++ + ++i , i = i++, etc…) I'm not able to understand the output of this program (using gcc).

Aug 29, 2021 · Those who want to use %n Format Specifier may want to look at this: Do Not Use the "%n" Format String Specifier. In C, use of the "%n" format specification in printf() and …

Jan 3, 2013 · The way x = a**d % n is calculated is to raise a to the d power, then modulo that with n. Firstly, if a is large, this creates a huge number which is then truncated. However, x = …

Dec 7, 2018 · In order to read the inputs one has to use an extra "%d" in scanf. For example: int a=1,b=2,c=3; scanf("%d %*d %d",&a,&b,&c); //input is given as: 10 20 30 O/p: a=10 b=30 and …